Wiman's type inequality for analytic and entire functions and h-measure of an exceptional sets

Authors

https://doi.org/10.15330/cmp.12.2.492-498

Keywords:

Wiman's inequality, analytic function, maximum modulus, maximal term, exceptional set, h-measure
Published online: 2020-12-30

Abstract

Let ER be the class of analytic functions f represented by power series of the form f(z)=+n=0anzn with the radius of convergence R:=R(f)(0;+]. For r[0,R) we denote the maximum modulus by Mf(r)=max |z|=r\} and the maximal term of the series by \mu_f(r)=\max\{|a_n| r^n\colon n\geq 0\}. We also denote by \mathcal{H}_R, R\leq +\infty, the class of continuous positive functions, which increase on [0;R) to +\infty, such that h(r)\geq2 for all r\in (0,R) and \int^R_{r_{0}} h(r) d\ln r =+\infty for some r_0\in(0,R). In particular, the following statements are proved.

1^0. If h\in \mathcal{H}_R and f\in \mathcal{E}_R, then for any \delta>0 there exist E(\delta,f,h):=E\subset(0,R), r_0 \in (0,R) such that \forall\ r\in (r_0,R)\backslash E\colon\ M_f(r)\leq h(r) \mu_f(r) \big\{\ln h(r)\ln(h(r)\mu_f(r))\big\}^{1/2+\delta} and \int\nolimits_E h(r) d\ln r < +\infty.

2^0. If we additionally assume that the function f\in \mathcal{E}_R is unbounded, then \ln M_f(r)\leq(1+o(1))\ln (h(r)\mu_f(r)) holds as r\to R, r\notin E.

Remark, that assertion 1^0 at h(r)\equiv \text{const} implies the classical Wiman-Valiron theorem for entire functions and at h(r)\equiv 1/(1-r) theorem about the Kövari-type inequality for analytic functions in the unit disc. From statement 2^0 in the case that \ln h(r)=o(\ln\mu_f(r)), r\to R, it follows that \ln M_f(r)=(1+o(1))\ln \mu_f(r) holds as r\to R, r\notin E.

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How to Cite
(1)
Skaskiv, O.; Kuryliak, A. Wiman’s Type Inequality for Analytic and Entire Functions and h-Measure of an Exceptional Sets. Carpathian Math. Publ. 2020, 12, 492-498.

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